The nonexistence of distance-regular graphs with intersection array {56,42,20;1,6,28} in which some local subgraph is the 7x8-grid.

Not scheduled
20m
Rogla, Slovenia

Rogla, Slovenia

Hotel Planja, Rogla 1, 3214 Zreče, Slovenia
Oral presentation

Speaker

Mikhail Golubyatnikov (Institute of Mathematics and Mechanics, Ural Branch of the Russian Academy of Sciences)

Description

There is an infinite sequence of formally self-dual classical distance-regular graphs $\Gamma$ with classical parameters $b=2$, $\alpha=1$, $\beta=n-1$, $v=n^3$ $(n>5)$.

If $n$ is a power of $2$, then there exists a distance-regular graph $\Gamma$ with intersection array $\{7(n-1),6(n-2),4(n-4);1,6,28\}$ and each distance-regular graph with these parameters is a bilinear forms graph. Moreover, all these graphs are locally grid.

We consider graphs $\Gamma$ with intersection array $\{7(n-1),6(n-2),4(n-4);1,6,28\}$, where $n$ is not a power of 2. By the results of Metsch, if $n\ge 71$, then graphs with intersection array $\{7(n-1),6(n-2),4(n-4);1,6,28\}$ don't exist.

If $n=6$, then the intersection array of $\Gamma$ is $\{35,24,8;1,6,28\}$. The nonexistence of a graph with this intersection array was proved by A. Jurishich and J. Vidali. The case when $n=7$ was ruled out by I.N. Belousov and A.A. Makhnev. The proof was based on counting of some triple intersection numbers.

In this work, we consider the case $n=9$. In this case, there are $6$ admissible spectra for the integral local subgraph. One of them is relate to the $7\times 8$-grid.

We prove that a distance-regular graph with intersection array $\{56,42,20;1,6,28\}$ does not exist, if some its local subgraph is the $7\times 8$-grid.

Acknowledgments. The work is supported by Russian Science Foundation (project 19-71-10067).

Primary author

Mikhail Golubyatnikov (Institute of Mathematics and Mechanics, Ural Branch of the Russian Academy of Sciences)

Presentation Materials